if the 9th term of an AP is zero prove that its 29th term is twice its 19th term
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a + 8d = 0
a = -8d
a + 28 d = 29 term
-8d + 28d = 29 term
29 term = 20 d
a + 18 d = 19 term
-8d + 18d = 19 term
19 term = 10d
2 * 19 term = 29 term
Proved
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