if the 9th term of an ap is zero prove that the 29th term is twice of its 19th term
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Answered by
13
Heya !!
9th term = 0
a + 8d = 0
a = -8d
To prove :
29th term = 2 ( 19th term )
a + 28d = 2 ( a + 18d )
-8d + 28d = 2 ( -8d + 18d )
20d = 2 ( 10d )
20d = 20d.......PROVED....
9th term = 0
a + 8d = 0
a = -8d
To prove :
29th term = 2 ( 19th term )
a + 28d = 2 ( a + 18d )
-8d + 28d = 2 ( -8d + 18d )
20d = 2 ( 10d )
20d = 20d.......PROVED....
kanu10490:
Thanks man
Answered by
2
Helo !
9th term = 0
a + 8d = 0
a = -8d
29th term = 2 ( 19th term )
a + 28d = 2 ( a + 18d )
-8d + 28d = 2 ( -8d + 18d )
20d = 20d..
hence,
lhs = rhs...
9th term = 0
a + 8d = 0
a = -8d
29th term = 2 ( 19th term )
a + 28d = 2 ( a + 18d )
-8d + 28d = 2 ( -8d + 18d )
20d = 20d..
hence,
lhs = rhs...
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