If the 9th term of an ap is zero then show that the 29th term is twice the 19th term
Answers
Answered by
24
Heya !!!
9th term = 0
A + 8D = 0
A = -8D
To prove :-
29th term = 2 ( 19th term )
A + 28D = 2 ( A + 1 8D )
-8D + 28D = 2 ( -8D + 18D )
20D = 2 ( 10D )
20D = 20D.....PROVED.....
★ HOPE IT WILL HELP YOU ★
9th term = 0
A + 8D = 0
A = -8D
To prove :-
29th term = 2 ( 19th term )
A + 28D = 2 ( A + 1 8D )
-8D + 28D = 2 ( -8D + 18D )
20D = 2 ( 10D )
20D = 20D.....PROVED.....
★ HOPE IT WILL HELP YOU ★
Answered by
12
Hey friend,
Here is your answer,
______________________________________________________________
Let the first term be a , common difference be d and number of terms be n.
Tn = a + (n-1)d
T₉ = a+8d = 0
=> a = -8d
T₁₉ = a+18d
Put a = -8d here.
T₁₉ = -8d+18d = 10d
T₂₉ = a+28d
Put a = -8d
T₂₉ = 20d
2*(T₁₉) = 2*10d = 20d = T₂₉
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
Here is your answer,
______________________________________________________________
Let the first term be a , common difference be d and number of terms be n.
Tn = a + (n-1)d
T₉ = a+8d = 0
=> a = -8d
T₁₉ = a+18d
Put a = -8d here.
T₁₉ = -8d+18d = 10d
T₂₉ = a+28d
Put a = -8d
T₂₉ = 20d
2*(T₁₉) = 2*10d = 20d = T₂₉
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
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