Question

If the 9th term of an ap is zero then show that the 29th term is twice the 19th term

Answer 1

Heya !!!




9th term = 0



A + 8D = 0


A = -8D



To prove :-


29th term = 2 ( 19th term )



A + 28D = 2 ( A + 1 8D )



-8D + 28D = 2 ( -8D + 18D )


20D = 2 ( 10D )



20D = 20D.....PROVED.....



★ HOPE IT WILL HELP YOU ★

Answer 2

Hey friend,

Here is your answer,
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Let the first term be a , common difference be d and number of terms be n.

Tn = a + (n-1)d

T₉ = a+8d = 0
     => a = -8d


T₁₉ = a+18d 
 Put a = -8d here.

T₁₉ = -8d+18d = 10d


T₂₉ = a+28d
Put a = -8d

T₂₉ = 20d



2*(T₁₉) = 2*10d = 20d = T₂₉
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