Question

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If the a, ß are the zeroes of p(x) = 5x^2 + 6x +1 then find
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Answer 1

Step-by-step explanation:

5x^2+6x +1

=5x^2 + 5x + x + 1

= 5x (x+1) + 1(x+1)

= (5x+1)(x+1)

5x+1=0 or x+1

x=-1/5. = α

or x=-1. =β

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