if the a.m of two number is 4.5 and their h.m is 4 then find numbers
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let numbers be a and b, then
Arithmetic Mean :
a+b / 2 = 4.5 or a+b = 9----I
Harmonic Mean : 2ab / (a+b) = 4
or ab=18 ----II
We have the sum and product from I and II, we need to find the a and b.
We will do it using Algebraic identity, (a+b)^{2} - (a-b)^{2} = 4ab
9^{2} - (a-b)^{2} = 4(18) a-b=3 ----III
Solve I and III for value of a and b
we get a=6 and b=3
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