Question

if the A.P is a=3 , d=2 than find tn and t10
a=3
d=2
tn= a+(n-1)d
= 3+ (n-1)2
= 3+2n-2
= 3-2+2n
= 2n-1Ans:-

t10= a+9d
= 3+9×2
= 3+18
= 21
Finally :-
tn=2n-1 and t10= 21Answer​

Answer 1

Answer:

Given : a=3, d=2

To find: t

n

and t

10

We have,

t

n

=a+(n−1)d

t

n

=3+(n−1)2

=3+2n−2

t

n

=2n+1

Now, n=10

So, t

10

=3+(10−1)2

=3 + 9×2

t

10

=3+18

t

10

=21

I hope this answer helpful for you