Physics, asked by sweetybee, 10 months ago

If the above impulse is applied to a 200 g model rocket at rest, what will be its final speed? (neglect gravity)
(2) 22.5 m/s
(1) 2.25 m/s
(3) 2250 m/s
(4) 4500 m/s
PLS HELP Me to solve! ​

Attachments:

Answers

Answered by maniamit12345
2

Answer:Impulse is equal to change in linear momentum or equal to force divided bt time .

Impulse is force× time it is applied

Impulse=m(v-u)/t (v=u+at)

450=200(v-0)/9

v=450×9/200

v=2.25 m/s

Explanation:

Similar questions