Question

If the absolute temperature of a gas is doubled and the pressure is reduced to one-
half, the volume of the gas will:

(a) Remain unchanged
(b) Be doubled
(c) Increase four-fold
(d) Be reduced to 1/4th​

Answer 1

Answer: (c) Increase four-fold

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = p

$P_2$ = final pressure of gas = $\frac{p}{2}$

$V_1$ = initial volume of gas = v

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = t

$T_2$ = final temperature of gas = 2t

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{p\times v}{t}=\frac{\frac{p}{2}\times V_2}{2t}$

$V_2=4\times v$

Therefore, the temperature of gas will increase four-fold.

Answer 2

Answer:

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Explanation:

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