Question

if the absolute temperature of a gas is increased by 3 times and pressure is reduced by 1/2 times. then what will volume become???

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Answer 1

Hey MATE!

We know that ideal gas equation states that PV = nRT, in which 'n' and 'R' remain constant for a given gas.

When we increase the temperature by 3 times and decrease pressure to one-third

then there is some change in volume.

Let us denote the n by V°.

So the new equation is :

PV°/2 = nR(3T) -----equation 2

PV = nRT ---------- equation 1

equation 2 ÷ equation 1

=> V°/2 = 3V

=> V° = 6V

So volume increases by 6 times.

Hope it helps

HAKUNA MATATA :))

Answer 2

Answer:It's volume is increased...

Explanation:bcz when we increase temp. Then the particle of matter(gas) are going away from initial position and when we decrease 〽 pressure the particle are going dou to large spaces ....

Hope it will help you