If the absolute temperature of a gas is raised to four times its original
temperature, how will its root-mean-square velocity be affected keeping all
other variables unchanged?
Answers
Answered by
41
Root-mean-square velocity of a gas is directly proportional to the root of absolute temperature of the gas. So if the absolute temperature is raised to 4 times its original temperature, the velocity will be doubled. (√4 = 2)
Answered by
13
Internal Energy of a given mass M of a gas (mass of each molecule = m) is given by the formula :
E = 1/2 M v² = 3/2 * R T
M = mass of gas
v = rms velocity = root mean square velocity
R = universal gas constant
T = absolute temperature of the gas
Energy of a molecule is given by : 1/2 m v² = 3/2 k_B T
k_B = Boltzmann's constant
m = mass of a molecule.
Thus v = √(3 R T / M) = √(3 k_B T/m)
For a given gas, the rms velocity depends only on the square root of the absolute temperature of the gas.
v2/v1 = √(T2/T1) = √4 = 2 So rms velocity becomes doubled.
E = 1/2 M v² = 3/2 * R T
M = mass of gas
v = rms velocity = root mean square velocity
R = universal gas constant
T = absolute temperature of the gas
Energy of a molecule is given by : 1/2 m v² = 3/2 k_B T
k_B = Boltzmann's constant
m = mass of a molecule.
Thus v = √(3 R T / M) = √(3 k_B T/m)
For a given gas, the rms velocity depends only on the square root of the absolute temperature of the gas.
v2/v1 = √(T2/T1) = √4 = 2 So rms velocity becomes doubled.
Similar questions