If the absolute temperature of a given quantity of gas is doubled and the pressure tripled, what happens to the volume of the gas?
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ANSWER: The volume quadruples.
EXPLANATION: We can use the combined gas laws to solve the problem.
p¹v¹ / t¹ = p²v²/ t²
Where
p¹ and p² are the pressure of the gases
v¹ and t² are the volumes
t¹ and t² are the Kelvin temperatures
We can rearrange the equation and get
v² = v¹ × p¹ /p² × t²/ t¹
In this problem
p¹= p¹;p²=0.5p¹
v¹=v¹;v²=?
t¹=t¹;t²=2v¹
there for v²= v¹= p¹/0.5p¹×2t¹/t¹=4v¹
v²/v¹=4v¹/v¹ = 4
Thus,doubling the Kelvin temperature and halving the pressure quadruple the volume.
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