Question

If the acceleration due to gravity at a height ‘h’ from the surface of the earth is 96% less than its value on the surface, then h is (where R is the radius of the earth).

Answer 1

Thank you for asking this question. Here is your answer:

g(h)=g(1–(2h/R))

According to question,

g at the height is 4% of g on Earth.

g(h)=4%ofg

=(4/100)g

.04g=g(1-(2h/R))

.04=1-(2h/R)

(2h/R)=.96

h=.48 R

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