Physics, asked by yatiawasthi9654, 1 year ago

If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body of mass m from the earth's surface to a height R equal to the radius of the earth is.

Answers

Answered by maya30
1

w=mgR/2
hope this will help you
Answered by ReRepeater
1

Explanation:

At earth surface

Ui = -Gmm / R

at the height h

Uf = -Gmm /2R

Therefore work done = Uf -Ui

                                     =  Gmm/R   = mgR /2

              Hope you understand

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