Question

If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body of mass m from the earth's surface to a height R equal to the radius of the earth is.

Answer 1

w=mgR/2
hope this will help you

Answer 2

Explanation:

At earth surface

Ui = -Gmm / R

at the height h

Uf = -Gmm /2R

Therefore work done = Uf -Ui

                                     =  Gmm/R   = mgR /2

              Hope you understand

This is Habel sabu .............Isn't it the Brainliest...............