Question

if the acceleration due to gravity is 10m/s2 at the surface of earth (radius 6400 m) then at a height of 1600 km the value of g will be

Answer 1

let g@e=10m/s/s
R@e=6400m
g'=?
hence,by Formula
[g'÷g@e]=[1-2(h÷R@e)]
thus g= -4.99×10^3(approx)

Answer 2

Answer: The value of g is 5 meter per second square.

Explanation:

The expression for the value of g at some height is as follows;

$g'=g(1-\frac{2h}{R})$

Here, g' is the value of acceleration due to gravity, h is the height and R is the radius.

It is given in the problem that the acceleration due to gravity is 10 meter per second square at the surface of earth (radius 6400 km).

Calculate the value of acceleration at height of 1600 km.

$g'=g(1-\frac{2h}{R})$

Put g= 10 meter per second square, R= 6400 km and h = 1600 km.

$g'=10(1-\frac{2(1600\times (1000\ km))}{6400\ km})$

$g'=5$

Therefore, the value of g' is  5 meter per second square.