Question

if the acceleration due to gravity on the earth is taken as 10 m/s² what will be the acceleration due to gravity on a planet whose mass is thrice the earth and whose radius is twice the earth​

Answer 1

Explanation:

acceleration due to gravity is given by g= GM/R^2

G is universal gravitational constant

and is constant everywhere in universe

Answer 2

Answer:

The acceleration due to gravity on a planet whose mass is thrice the earth and whose radius is twice the earth​ is 7.5 m/s².

Explanation:

The acceleration due to gravity is given by the equation,

g = GM /R²

Where 'G' is the universal gravitational constant, 'M' and 'R' are the mass and radius of the planet whose acceleration due to gravity is to be found.

We know the value of g on the surface of the earth is 9.8 m/s². Here we take it as 10 m/s² for easy calculations.

∴ g = GM /R² = 10 m/s²

If the mass of the planet is thrice the mass of the earth, then its mass can be written as M' = 3M.

If the radius of the planet is twice that of the earth, then its radius can be written as R' = 2R.

Now the acceleration due to gravity opf the planet can be found as:

g' = GM' /R'²

g' = G 3M /(2R)²

g' = 3/4 × GM /R²

g' = 3/4 × 10

g' = 7.5 m/s²