Question

If the acceleration due to gravity on the surface of the earth is 9.8 m/s2. What will be the acceleration due to gravity on the surface of a planet whose mass and radius both are two times the corresponding quantities for the earth​

Answer 1

$g \propto GM R^ 2; \\ So, \\ g p =( \frac{M ^ p}{M ^ e} \times ( \frac{R e}{R p ^2} )g; \\ =2 \times ( \frac{1}{2 ^2}) g; \\ = g 2 =4.9 m/s^ 2$

Answer 2

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