Question

If the acceleration of block is 10 m/sec2
then coefficient of kinetic friction between
block and the surface is :
4 kg
→ F= 60 N​

Answer 1

Answer:

From FBD of 10 kg block,

F=30N,f=0.1×10×10=10N (Assuming kinetic friction coefficient =0.1)

As F>f , so the 10 kg block will move with acceleration a.

Thus, 10a=F−f=30−10=20⇒a=2m/s

2