Question

If the activation energy is zero then the rate constant k at 300k is equal to

Answer 1

Dear Student,Activation energy = 0Rate constant when temperature, T1= 298 K, (K1)= 1.6 ×106 s−1Rate constant when temperature, T2= 300K, (K2) =?logK2K1 =Ea2.303(T2−T1T2T1)logK2K1 =02.303(T2−T1T2T1)logK2K1 =0logK2K1 =Antilog 0K2K1 =1K2 =K1 =1.6 ×106 s−1

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