If the acute angle between the lines 2x + 3y - 5 = 0 and 5x + ky-6-0 is π\4 Then find the value of k.
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Step-by-step explanation:
We know that, if y=mx+c is the equation of an straight line, then m is called the slope of the equation.
For the straight line,
4x−y+7=0
⟹y=4x+7
Therefore, m1=4 is the slope of the above equation.
Similarly, for the straight line,
kx−5y−7=0
⟹y=5kx+59
Therefore, m2=5k is the slope of the above equation.
The angle two two straight lines is given as:
tanθ=∣∣∣∣∣1+m1m2m1−m2∣∣∣∣∣
Therefore, the angle between the given straight lines is given as
tan450=∣∣∣∣∣∣∣∣1+4×5k4−5k∣∣∣∣∣
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