Question

If the adjacent angle of a parallelogram are (2x+12) and (3x-62) find the angle of parallelogram
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Answer 1

adjacent angle of parallelogram is supplementary

2x+12+3x-62=180

5x-50=180

5x=180+50

5x=230

x=230/5=46

2x+12=2×46+12

=92+12=104

3x-62=3×46-62

=138-62

=76

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Answer 2

Step-by-step explanation:

We know that,

Adjacent angles are equal to 180°

According to the question :

➡ (2x + 12)° + (3x - 62)°

➡ 2x + 12 + 3x - 62 = 180°

➡ 62 - 12 + 3x + 2x = 180°

➡ 5x - 50 = 180°

➡ 5x = 180° + 50°

➡ 5x = 230°

➡ x = 230/5

➡ x = 46°

Hence,

The two adjacent angles are :

➡ (2x + 12)° = 104°

➡ (3x - 62)° = 76° ans.