Question

If the adjacent angles of a parallelogram are (2x + 12) and (3x 62), find the angles of the parallelogram

Answer 1

as we know that sum of two parallel sides of a parallelogram is 180°.so,

(2x+12)+(3x-62)=180

5x-50=180

5x=230

x=46°

so angles are

2×46+12=104°

and3×46-62=76°

Answer 2

Step-by-step explanation:

We know that,

➡ Adjacent angles are equal to 180°

According to the question :

➡ (2x + 12)° + (3x - 62)°

➡ 2x + 12 + 3x - 62 = 180°

➡ 62 - 12 + 3x + 2x = 180°

➡ 5x - 50 = 180°

➡ 5x = 180° + 50°

➡ 5x = 230°

➡ x = 230/5

➡ x = 46°

Hence,

The two adjacent angles are :

➡ (2x + 12)° = 104°

➡ (3x - 62)° = 76° ans.