Question

If the age of 2 boys are 4:7. 8 years ago their age was 1:2. What is their present age?

Answer 1

Answer:

Their present ages are 32 and 56 respectively.

Step-by-step explanation:

Let the age of the two boys be 4x and 7x

By condition,

4x - 8 / 7x - 8 = 1/2

=> 2(4x - 8) = 7x - 8

=> 8x - 16 = 7x - 8

=> 8x - 7x = 16 - 8 => x = 8

Present age of first boy = 4x = 4×8 = 32

Present age of 2nd boy = 7x = 7×8 = 56.

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