if the age of father is twice of his son and 16 years ago father age is six times of his son find the present age of father and son
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Let the present age of father's be x years and
present age of son's be y years.
According to the problem
X = 6y
After 4 years
x+4 = 4(y + 4)
Hence we get two equations
⟶X = 6y ________________________ (1)
⟶X +4 = 4(y + 4) ___________________ (2)
Simplifying eq (2)
⟶x + 4 = 4y + 16
⟶x - 4y = 12
Put x 6y in eq (2), we get
⟶6y - 4y = 12
⟶2y = 12
⟶y = 6 years
and x = 6y = 36 years
Present age of son = 6 years
and present age of father = 36 years
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