Question

If the alpha and beta are zeroes of 2 x^2+5 x-10, then the value of αβ is: ​

Answer 1

AnsWer :

- 5.

SolutioN :

2x² + 5x - 10.

☯ Compare With General Expression.

ax² + bx + c = 0.

Where as,

• a = 2.
• b = 5.
• c = - 10.

☛ Sum Of Zeros.

→ α + β = - b / a.

$\rule{50}1$

☛ Product Of Zeros.

→ αβ = c / a.

$\rule{90}2$

✎ Let's Find the value of :

→ αβ = c / a.

→ - 10 / 2.

→ - 5.

✡ Therefore, the value of αβ is - 5.

Answer 2

Answer:-5

Step-by-step explanation:

alpha+beta =-b/a

alphabeta =c/a

a=2, b=5 and c=-10

Therefore,

alphabeta = c/a

Which is = -10/2

=-5