If the altitude of an equilateral triangle is 6^1/2, find it's area.
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h=root6
root3/2 a = root6
root3a =2 ×root6
root3a = 2× root3 × root2
a= 2×root2
a=2root2
area = root3/4 a^2
= root3/4 × (2root2) ^2
=root3/4 × 4×2
= 2×root3
area= 2root3 is answer
root3/2 a = root6
root3a =2 ×root6
root3a = 2× root3 × root2
a= 2×root2
a=2root2
area = root3/4 a^2
= root3/4 × (2root2) ^2
=root3/4 × 4×2
= 2×root3
area= 2root3 is answer
Iashimaj6:
The answer is 2√2 sq.units.
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