Question

If the altitude of the Sun at a certain time is 60°, what is the height of the tower that casts a shadow of length 36 m at that time?
I

Answer 1

Step-by-step explanation:

FIRST REFER THE ATTACHMENT FOR THE FIGURE.

$\tan( \alpha ) = \frac{perpendiulr}{base}$

$\tan(60 ) = \frac{ab}{bc}$

$\sqrt{3} = \frac{x}{36m}$

$36 \sqrt{3}m = x$

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