Question

If the amount after 3 years at the rate of 25 upon 2 per annum compounded anually is ₹10935,find the principal

Answer 1

A=P(1+R100)t

P = 10800, R =1212% and t = 3 years

So, A=10800(1+25200)3

=10800(1+18)3

=10800(98)3

=10800×98×98×98=15377.34

So, Interest =A–P

=15377.54-10800=4577.34

Answer 2

QUESTION

If the amount after 3 years at the rate of 25 upon 2 per annum compounded anually is ₹10935,find the principal




TOPIC => COMPOUND INTEREST

SOLUTION




GIVEN =>



COMPOUND INTEREST=Rs 10935



Time=3years



RATE=$\frac{25} {2}$




FORMULA USED

COMPOUND INTEREST=A-P

A. IS AMOUNT

P IS PRINCIPAL

SO



$c.i = p {(1 + \frac{r}{100}) }^{3} + p$




therefore


$10935 = p(1 + ({1 + \frac{r}{100} )}^{3} )$




$10935 = p(1 + ( {1 + \frac{25}{100×2}) }^{3}$




$10935 = p(1 + ( \frac{1}{8} \times \frac{1}{8} \times \frac{1}{8} ))$




$10935 = p(1 + \frac{1}{512} )$





$p = \frac{513}{512} \times 10935$


$p =\frac{5,609,655}{512}$



principal=rs 10,956.3574