Question

If the amount bf Rs. 400/- for 2 years is 441 then find the annual rate of compound interes
solve kardijiye pls !!
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Answer 1

Answer:

Correct Answer:

A) RS.484

Step-by-step explanation:

$= > 441400 = (1 + \frac{r}{100} {)}^{2}$

$441 = 400( 1 + \frac{r}{100} {)}^{2}$

$= > ( \frac{21}{20} )^{2} = (1 + \frac{r}{100} {)}^{2}$

$= > \frac{21}{20} = 1 + \frac{r}{100}$

$= > \frac{21}{20} - 1 \frac{r}{100} = > \frac{r}{100} = \frac{1}{20}$

R=5%

New rate = 5+5=10%

$amount \: = 400(1 + \frac{10}{100} {)}^{2}$

$= > 400 \times \frac{11}{10} = rs.484$

Hope it's help you....

Answer 2

Using the formula

A= P(1+r/100)^t

where t is the time period in years r is the rate, P is the principal and A is the amount so

441=400(1+r/100)²

441/400=(1+r/100)²

(21/20)²=(1+r/100)²

21/20–1=r/100

1/20=r/100

So,

R=5%

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