Question

If the amount bf Rs. 400/- for 2 years is 441 then find the annual rate of compound interest


pls faltu ke añswer mat karo​

Answer 1

Answer:

★Rs. 486

Step-by-step explanation:

★According to the given condition

$441 = 400(1 + \frac{r}{100} {)}^{2}$

$= 441(1 + \frac{r}{100} {)}^{2}$

$= ( \frac{21}{20} {)}^{2} = (1 + \frac{r}{100} {)}^{2}$

$= \frac{21}{20} = 1 + \frac{r}{100}$

$= \frac{21}{20} - 1 = \frac{r}{100} = > \frac{r}{100} = \frac{1}{20}$

❥R = 50 %

New rate = 5 + 5 = 10 %

$= > 400 \times \frac{11}{10} \times \frac{11}{10} = rs.484$

★★Hope it's help you.....★★