Question

If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima is(a) 25 : 16(b) 5 : 3
(c) 16 : 1(d) 25 : 9

Answer 1

Correct answer is c

16:1

Answer 2

Answer:

(c) 16 : 1 is the correct answer.

Explanation:

Given data:

amplitude ratio of two sources producing interference = 3 : 5

To find

the ratio of intensities at maxima and minima =?

Intensity is given by I

Imax/Imin = (a1+a2/a1-a2) ^2

=[ (1+3/5) / (1-3/5) ]^2

= (8/5) ^2/ (2/5) ^ 2

=64/4

=16/1

Thus the ratio of maximum to minimum intensity is 16:1.

Hence, c) 16 : 1 is the correct answer.

Note : The average amount of energy passing through unit area is called as intensity.

The wave which carries high energy is high amplitude wave.

The wave which carries low energy is low amplitude wave.