If the angle A of a rhombus ABCD is 120 degree,prove that the triangle is equilateral.
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join both the diagnol
now in the small ∆ABO. o being the intersection point of diagonal
now, angle OAB = half of angle A=60°
similarly, angle OBA=60°
with ASP
angle O=60°
hence ∆ is equilateral
now in the small ∆ABO. o being the intersection point of diagonal
now, angle OAB = half of angle A=60°
similarly, angle OBA=60°
with ASP
angle O=60°
hence ∆ is equilateral
SanyamTaneja:
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