If the angle at the vertex of an isosceles triangle is 38⁰, what is the measure of either one of the base angles?
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Answer:
We know that the sum of angles of a Triangle is 180°
Let base angle be b
Then, b + b + 40° = 180°
= 2b + 40 = 180°
By Transposing 40 from LHS to RHS it becomes -40
= 2b = 180 – 40
= 2b = 140
Now, Divide both the side by 2
= 2b/2 = 140/2
= b = 70°
Hence, 70° is the base angle of an isosceles Triangle
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Answer:
We know that sum of all the angle of triangle is 180and in isosceles triangle the sides are equal .
therefore the two angle is also equal
Let the base angle be x =x+x
=2x
2x + 38 = 180
2x = 180 - 38
2x = 142
x = 142/2
x = 71°
the measure of one of the base angle is 71°
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