Question

if the angle between the asymptotes of a hyperbola x^2/a^2-y^2/b^2=1 is theta, then the value of sec theta/2 is:​

Answer 1

Answer:

D

e

2

−1

e

tan

2

θ

=

a

b

⇒e

2

−1=tan

2

2

θ

⇒sec

2

θ

=e

or e

2

−1=cot

2

2

θ

⇒cosec

2

θ

=e

⇒sec

2

θ

=

e

2

−1

e

.