Question

if the angle between the axis and polarizer and analyser is 90° the intensity of light transmitted by analyser is how Many times the intensity of transmitted by the polariser​

Answer 1

Answer:

Concept:

When polarized light of intensity $I_{0}$ is incident on a polarizer, the transmitted intensity is given by $I=I_{0} \cos ^{2} \theta$, where is the angle between the incident light's polarization direction and the filter's axis. The transmitted light is polarized along the polarizer's axis.

Step-by-step explanation:

The angle between the axis of the polarizer and analyzer = 90°

$I=I_{0} \cos ^{2} \ 90$

$I=I_{0} \ 0$

$I = 0$

This "paradoxical" effect is a defining characteristic of wave phenomena in general.

#SPJ2

Answer 2

Answer:

If the intensity Io of polarized light occurs in the polarizer, the transmitted intensity is given by I=Iocos2θ the angle between the polarization direction of the incident light and the filter axis. The transmitted light is polarized along the axis of the polarizer.

Step-by-step explanation:

As it passes through the polarizing material, the light polarizes and, as a result, its intensity changes. This change depends on the angle between the polarization direction and the material axis. It also depends on the original light intensity. The intensity I of the polarized light after passing through the polarizer and after passing through the analyzer is;

I = Io²cos²0

Where Io is the original light intensity and θ is the angle between the gasizer and the analyzer.

The angle between the axis of the polarizer and analyzer = 90°

I=Iocos²90

I=Io0

I=0

#SPJ2

This "paradoxical" effect is a defining characteristic of wave phenomena in general.