If the angle between the axis of polariser and the analyser is 45°, write the ratio of the intensities of original light and the transmitted light after passing through the analyser.
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Answer:
Ratio is 2 : 1
Explanation:
Let I' and I be the transmitted light and original light
According to Malu's law
I' = I cos²∅
given: ∅ = 45°
I' = I (cos 45° )²
I' = I ( 1 / 2 )
I / I' = 2
I : I' = 2 : 1
Hence you got the ratio !
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