Question

if the angle between the curves y^(2)=4x and y=e^(-x/2) is theta then the value of cos ec^(2)(theta/2) is​

Answer 1

Step-by-step explanation:

x2=y=1. y=e 2(1-x)

tan Q = m1-m2 by 1 + m1 m2

x2y= 1

2x-y+ x2-y1=0

= y1 - 2xy by x2 = 2-2y by x

y1.= m1.= -2(-1) by 1 = -2

y=e 2(1-x)

dy/dn= e -2

m2 = dy/dn (1,1) = e -2 = -2

therefore tanQ = (-2)-(-2) / 1+(-2)(-2)

= -2 + -2 / 1+4 = 0 -2 cancelled

= tanQ= 0 / Q=0