if the angle between the vectors a and vector b is theta the value of the product of brexit b vector into a vector bracket close . a vector is equal to
Answers
Answered by
277
let BxA = R
BxA is a vector which is perpendicular to both B & A ...
(BxA).A = R.A
R perpendicular to A so dot product will be 0 ...
(dot product of any two perpendicular vectors is 0)
so , (BxA).A =0
BxA is a vector which is perpendicular to both B & A ...
(BxA).A = R.A
R perpendicular to A so dot product will be 0 ...
(dot product of any two perpendicular vectors is 0)
so , (BxA).A =0
Answered by
658
Hello dear,
● Answer -
(a×b).a = 0
● Explaination -
Consider θ be the angle between vector a & vector b.
Let's find out (a×b).a
(a×b).a = (a.a)×(b.a)
(a×b).a = (0)×(b.a)
(a×b).a = 0
Therefore, value of (a×b).a is 0.
# Important concepts used here -
1) Dot product of vector with itself is zero.
a.a = 0
2) Cross product of any vector with zero vector becomes zero.
0×r = 0
Hope this helps you clear concepts.
Thanks for the question.
● Answer -
(a×b).a = 0
● Explaination -
Consider θ be the angle between vector a & vector b.
Let's find out (a×b).a
(a×b).a = (a.a)×(b.a)
(a×b).a = (0)×(b.a)
(a×b).a = 0
Therefore, value of (a×b).a is 0.
# Important concepts used here -
1) Dot product of vector with itself is zero.
a.a = 0
2) Cross product of any vector with zero vector becomes zero.
0×r = 0
Hope this helps you clear concepts.
Thanks for the question.
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