If the angle between two tangents drawn from an external point “P to a circle of radius
and centre O is 60°, then find the length of OP.
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Given that
Angle between two tangent is 60°
angle APB = 60°
Now,
In ∆OPA and ∆ OPB
angle OAP = angle OPB ( both 90°)
OP = OP ( common )
OA = OB ( both radius )
∆ OPA = ∆ OPB ( RHS congruency )
angle OPA = angle OPB ( CPCT )
so, we can write ,
angle OPA = angle OPB = 1/2 angle APB
so, angle OPA = 1/2 × 60° = 30°
Now , In ∆ OPA
sin P = OA/OP
sin 30° = r/OP
1/2 = r/OP
OP = 2r
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