Question

If the angle between two vectors of equal magnitude P is 0, the magnitude of the
resultant vector is​

Answer 1

Given :-

$\theta = 0$

To find :-

The magnitude of resultant vector.

Solution:-

Since,

The angle between vectors is 0°.

hence,They are parallel vectors.

→$\theta = 0^{\circ}$

• Multiplying both side by Cos.

→$Cos \theta = Cos0^{\circ}$

→$Cos \theta = 1$

Now,

• Using addition law of vector

The magnitude of resultant vector is given by :-

→$R = \sqrt{A^2 + B^2 + 2AB Cos \theta}$

• Magnitude of both vector is p.

→$R = \sqrt{p^2 + p^2 + 2p \times p Cos \theta}$

→$R = \sqrt{2p^2 + 2p^2 \times 1}$

→$R = \sqrt{4p^2}$

→$R = 2p$

hence,

The magnitude of resultant vector is 2p.

Conclusion → When the angle between the two equal vector is 0°.

Then, the resultant is equal to sum of two magnitude of two equal vectors.