Question

If the angle between vectors with magnitude 12 and 4 is 60% than their scalar product is

Answer 1

Answer:

1 is the answers it's explanation is down below

Explanation:

Given, both vectors have same magnitude i.e., ∣a∣=∣b∣ and scalar product of vectors, a⋅b=

2

1

(given).

Let θ be the angle between two vectors a and b. Then,

cosθ=

∣a∣∣b∣/a⋅b

⇒cos60

∘

=

∣a∣∣a∣/2/1

[∵∣a∣=∣b∣(given)]

⇒

2/1

=

2∣a∣/2/1

⇒∣a∣=1

∴∣a∣=∣a∣=1.