if the angle of a parallelogram is two thirds of its adjacent angle,find the angles of the parallelogram
ch mid point theorem
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Angle of the parallelogram is two third of its adjacent angle
So let one of the angle be x
So x+2x/3=180
5x/3=180
x=36×3=108
So the other (adjacent )angle is 180-108=72
So all angles of the parallelogram are 108,72,108,72 (all in degrees)
So let one of the angle be x
So x+2x/3=180
5x/3=180
x=36×3=108
So the other (adjacent )angle is 180-108=72
So all angles of the parallelogram are 108,72,108,72 (all in degrees)
soukarsha:
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hey but how have u find rest 2 angles
If you find two angles of the parallelogram then you can also find the other two angles as in a parallelogram opposite angles are equal
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