If the angle of a quadrilateral are x (x-10) (x+30) and 2x then the greatest angle is
Answers
Answered by
29
by angle sum property of quadrilateral
X + X - 10 + X + 30 + 2 x= 360
5 x + 20=360
5x=340
x=68
now the angles are 68, 58, 98, 136
show the biggest angle is 136 that is 2x
X + X - 10 + X + 30 + 2 x= 360
5 x + 20=360
5x=340
x=68
now the angles are 68, 58, 98, 136
show the biggest angle is 136 that is 2x
Answered by
18
By angle sum property of a quadrilateral,
x+ (x-10) + (x+30)+ 2x = 370°
5x -10 + 30 = 360
=> 5x + 20 = 360
=> 5x= 360 - 20 = 340
=> x = 340/5
=> x= 68
Then, the measure of angles are 68°, 58°, 98° and 136°•
So, the greatest angle is 2x i. e. 136° Ans
x+ (x-10) + (x+30)+ 2x = 370°
5x -10 + 30 = 360
=> 5x + 20 = 360
=> 5x= 360 - 20 = 340
=> x = 340/5
=> x= 68
Then, the measure of angles are 68°, 58°, 98° and 136°•
So, the greatest angle is 2x i. e. 136° Ans
Similar questions