if the angle of a quadrilateral X°,(x+30)°,(x-10)° and 2x° , find the measure of greatest angle
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Answered by
4
As we know
the sum of measures of angles of quadrilateral is 360
so
x+x+30+x-10+2x=360
5x+20=360
5x=340
x=68
greatest angle
=2x
=2×68
=136
the sum of measures of angles of quadrilateral is 360
so
x+x+30+x-10+2x=360
5x+20=360
5x=340
x=68
greatest angle
=2x
=2×68
=136
Khushi100100:
but answer is ...136°... is the greatest ...
Answered by
1
total angle = 360
x+(x+3)+(x-10)+2x=360
3x+(x+30)+(x-10)= 360
3x+(x+30)+x=360+10=370
4x+x=370-30=340
5x=340
x= 340÷5
x=68
greatest angle is 2x
2x= 2×68
=136 digre
x+(x+3)+(x-10)+2x=360
3x+(x+30)+(x-10)= 360
3x+(x+30)+x=360+10=370
4x+x=370-30=340
5x=340
x= 340÷5
x=68
greatest angle is 2x
2x= 2×68
=136 digre
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