if the angle of a triangle are in the ratio 1:1:2 then find the ratios of the perimeter of the triangle to the longest side.
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let the angles be x , x and 2x
we know
x + x + 2x = 180°
4x = 180°
x = 45°
now the angles are -
45° , 45° and 2(45) = 90°
so it is an isoceles right angles triangle
In an isosceles right triangle, the equal sides make the right angle.
They have the ratio of equality, 1 : 1.
To find the ratio
let the length of the hypotenuse be h,
according to the Pythagorean theorem,
h^2 = 1^2 + 1^2 = 2.
Therefore,
h = root(2)
the ratio is - 1:1:root(2)
we know
x + x + 2x = 180°
4x = 180°
x = 45°
now the angles are -
45° , 45° and 2(45) = 90°
so it is an isoceles right angles triangle
In an isosceles right triangle, the equal sides make the right angle.
They have the ratio of equality, 1 : 1.
To find the ratio
let the length of the hypotenuse be h,
according to the Pythagorean theorem,
h^2 = 1^2 + 1^2 = 2.
Therefore,
h = root(2)
the ratio is - 1:1:root(2)
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