Question

If the angle of elevation of a tower from a distance of 100 meters from its foot is 60?, the height of the tower is ​

Answer 1

Answer:

100 /√3 = 57.74

Step-by-step explanation:

tan 60°= height of tower/ distance of 100

1 / √3 = height/ 100

100 / √3 =height

Answer 2

Answer:

height of the tower is 173.2 m.

Step-by-step explanation:

angle of elevation= 60⁰

distance = 100

height = ?

tan A = perpendicular/ base

tan 60⁰ = h/100

√3 = h / 100

√3×100 = h

put√3 = 1.732

1.732 × 100 = h

h= 173.2 m.

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