Math, asked by soham28x, 9 months ago

If the angle of elevation of a tower from a distance of 100 meters from its foot is 60?, the height of the tower is ​

Answers

Answered by nirmalkumarm30
1

Answer:

120....................

Answered by nilimbora
2

Answer:

100√3

Step-by-step explanation:

we know, Tan60°=√3

tan60°= side opposite/side adjacent

√3= AC/BC [let the hight of right angle∆ be AC and base be BC

Now,

√3=AC/100

AC= 100√3

therefore hight of the tower is 100√3 m

Hope it was helpful

and sorry if I couldn't make it clear to you

Thank you ❤

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