If the angle of elevation of a tower from a distance of 100 meters from its foot is 60?, the height of the tower is
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Answered by
1
Answer:
120....................
Answered by
2
Answer:
100√3
Step-by-step explanation:
we know, Tan60°=√3
tan60°= side opposite/side adjacent
√3= AC/BC [let the hight of right angle∆ be AC and base be BC
Now,
√3=AC/100
AC= 100√3
therefore hight of the tower is 100√3 m
Hope it was helpful
and sorry if I couldn't make it clear to you
Thank you ❤
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