Question

If the angle of elevation of a tower from a distance of 100 m from its foot is 60 degree, then the height of the tower is

Answer 1

Hence, height of the tower is 173.m

Answer 2

The height of tower is 173.2 m

Step-by-step explanation:

Distance between the point and the foot of tower = Base = 100 m

Angle of elevation = 60°

We are supposed to find the height of tower i.e. Perpendicular

So,$Tan \theta = \frac{Perpendicular}{Base}$

$Tan 60^{\circ}=\frac{Height}{100}$

$\sqrt{3} \times 100 = Height$

173.2 =Height

Hence The height of tower is 173.2 m

#Learn more:

The angle of the elevation of the top of the tower from a 60 metre from its foot is 30 degrees find the height of the tower ​

https://brainly.in/question/11198735