If the angle of elevation of a tower from a distance of 75 m from its foot is 60°, then the height of the tower is
(a) 25sqrt root 3 m
b) 50sqrt root 3m
(c) 75sqrt root 3m
(d) 10sqrt root 3m
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Answer:
Step-by-step explanation:
Let h be height of tower then In ΔABC
BC
AB
=tan60
∘
100
h
=
3
h=100
3
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