Question

If the angle of elevation of the top of a tower from a point which is d mt from its foot is theta . Then the height of the tower is

Answer 1

The height of such a tower having $\theta$ as the angle of elevation from a point and distance $d$ from the foot of that tower to the point is $dtan\theta$.

Explanation:

• We know that in a right angled triangle having perpendicular length 'p' and base length 'b' corresponding to angle $\alpha$ we have, $tan \alpha= \frac{p}{b}$
• Here the point on the ground, the top of the tower, and the foot of the tower form a right angled triangle.
• In this triangle for the angle of elevation $\theta$ we have, $tan\theta=\frac{p}{b}$
• Here, 'p' is the height of the tower and 'b' is the distance of the point on the ground from the foot of the tower.  
• Hence, we get $tan\theta=\frac{h}{d} \ \ \ \ \ ->h=dtan\theta$
• Therefore the height of the tower in terms of angle of elevation and distance from the foot the tower is $dtan\theta.$

Answer 2

Answer:

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