Question

If the angle of elevation of tower from a distance of 110 meter from its foot is 60°
The height of the tower is​

Answer 1

Answer:

Step-by-step explanation:

make a right angle triangle ABC

AC is hypotenuse , AB is perpendicular and BC is base

Let 'h' be height of tower then In Δ ABC

∴ AB = h , BC = 110 (given) , ∠ACB = 60°

tan 60° = $\frac{AB}{BC}$

$\sqrt{3} =\frac{110}{h}$

h = $110\sqrt{3}$